If `y` is a function of `x and log(x+y)-2xy=0` then the value of `y (0)` is equal to (a) `1` (b) `-1` (c) `2` (d) `0`A. 1B. -1C. 2D. 0

If `y` is a function of `x and log(x+y)-2xy=0` then the value of `y (0

1.	If `y` is a function of `x and log(x+y)-2xy=0` then the value of `y (0)` is equal to (a) `1` (b) `-1` (c) `2` (d) `0`A. 1B. -1C. 2D. 0
Answer» Correct Answer - A When x=0, we have `log(0+y)-2xx0xxy=0implieslogy=0impliesy=1` Now, `log(x+y)-2xy=0` Differentiating with respect to x, we get `(1)/(x+y)(1+(dy)/(dx))-2y-2x(dy)/(dx)=0` Putting x=0 and y=1, we get `(1+(dy)/(dx))-2-2xx0=0implies(dy)/(dx)=1`

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