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If for `x (0,1/4),`the derivative of `tan^(-1)((6xsqrt(x))/(1-9x^3))`is `sqrt(x)dotg(x),`then `g(x)`equals:`(3x)/(1-9x^3)`(2) `3/(1+9x^3)`(3) `9/(1+9x^3)`(4) `(3xsqrt(x))/(1-9x^3)`A. `(3)/(1+9x^(3))`B. `(9)/(1+9x^(3))`C. `(3xsqrt(x))/(1-9x^(3))`D. `(3x)/(1-9x^(3))` |
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Answer» We have `y=tan^(-1)((6xsqrt(x))/(1-9x^(3)))` `=tan^(-1)((2cdot(3x^(3//2)))/(1-(3x^(3//2))^(2)))=2 tan ^(-1)(3x^(3//2))` `therefore" "(dy)/(dx)=2xx(1)/(1+9x^(3))xx3xx(3)/(2)xxx^(1//2)=(9sqrt(x))/(1+9x^(3))` `therefore" "g(x)=(9)/(1+9x^(3))` |
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