If `y=(sin^(-1)x)/(sqrt(1-x^2)),t h e n((1-x^2)dy)/(dx)`is equal to`x+y`(b) `1+x y``1-x y`(d) `x y-2`A. x+yB. 1+xyC. 1-xyD. xy-2

If `y=(sin^(-1)x)/(sqrt(1-x^2)),t h e n((1-x^2)dy)/(dx)`is equal to`x+

1.	If `y=(sin^(-1)x)/(sqrt(1-x^2)),t h e n((1-x^2)dy)/(dx)`is equal to`x+y`(b) `1+x y``1-x y`(d) `x y-2`A. x+yB. 1+xyC. 1-xyD. xy-2
Answer» `y=(sin^(-1))/(sqrt(1-x^(2)))` `therefore" "(dy)/(dx)=(sqrt(1-x^(2))(1)/(sqrt(1-x^(2)))-(sin^(-1)x)(1)/(2)((-2x))/(sqrt(1-x^(2))))/(1-x^(2))` `"or "(1-x^(2))(dy)/(dx)=1+x((sin^(-1)x)/(sqrt(1-x^(2))))=1+xy`

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Find `(dy)/(dx)`, when: `y=e^(x)sin^(3)xcos^(4)x`
If y= sin px and `y_(n)` is the nth derivative of y, then `|{:(y,y_(1),y_(2)),(y_(3),y_(4),y_(5)),(y_(6),y_(7),y_(8)):}|`isA. 1B. 0C. -1D. none of these
Find `(dy)/(dx)`, when: `y=2^(x).e^(3x)sin4x`
Find the second derivative of `e^(3x)sin4x.`
If for `x (0,1/4),`the derivative of `tan^(-1)((6xsqrt(x))/(1-9x^3))`is `sqrt(x)dotg(x),`then `g(x)`equals:`(3x)/(1-9x^3)`(2) `3/(1+9x^3)`(3) `9/(1+9x^3)`(4) `(3xsqrt(x))/(1-9x^3)`A. `(9)/(1+9x^(3))`B. `(3xsqrt(x))/(1-9x^(3))`C. `(3x)/(1-9x^(3))`D. `(3)/(1+9x^(3))`
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If for `x (0,1/4),`the derivative of `tan^(-1)((6xsqrt(x))/(1-9x^3))`is `sqrt(x)dotg(x),`then `g(x)`equals:`(3x)/(1-9x^3)`(2) `3/(1+9x^3)`(3) `9/(1+9x^3)`(4) `(3xsqrt(x))/(1-9x^3)`A. `(3)/(1+9x^(3))`B. `(9)/(1+9x^(3))`C. `(3xsqrt(x))/(1-9x^(3))`D. `(3x)/(1-9x^(3))`
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If `f(theta) = sin(tan^(-1)(sintheta/sqrt(cos2theta)))`, where `-pi/4 lt theta lt pi/4,` then the value of `d/(d(tantheta)) f(theta)` is