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If `y=|x-x^(2)|`, then `(dy)/(dx)" at "x=1`.A. -1B. 1C. does not existD. none of these |
Answer» Correct Answer - C We have, `y=|x-x^(2)|-{{:(x-x^(2)","," if "-1lexle1),(x^(2)-x","," if "|x|le1):}` Dlearly, y is continuous at x=1 but it is not differentiable at x=1, because `("LHD at "x-1)=((d)/(dx)(x-x^(2)))_("at "x=1)=1-2=-1` `("RHD at "x=1)=((d)/(dx)(x^(2)-x))_("at "x=1)=2-1=1`. Hence, `(dy)/(dx)" at "x=1` does not exist. |
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