1.

If |z| = 6 and arg(z) `=(3pi)/(4)`, find z.

Answer» Correct Answer - `z = 3 sqrt(2) (-1 + i)`
`z=6("cos"(3pi)/(4)+ "i sin"(3pi)/(4))=6{cos(pi-(pi)/(4))+i sin(pi-(pi)/(4))}`
`rArr" "z=6("-cos"(pi)/(4)+"i sin"(pi)/(4))=6((-1)/(sqrt(2))+i.(1)/(sqrt(2)))=(6)/(sqrt(2))(-1+i)`
`rArr" "z = 3 sqrt(2) (-1+i)`.


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