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Ifthe distance travelled by a body in the nth second is given by (4+ 6 n) m then find theinitial velocity and acceleration of the body. |
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Answer» Snth= u + a(n-1/2) = u -a/2 + an Snt= 4 + 6n (given) comparing both equations u-a/2 = 4 , a = 6m/s^2 u = 4+a/2 = 7m/s |
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