Ii) how to find? can any one help

1.	Ii) how to find? can any one help
Answer» Answer: 1.As you can see the effective resistance is 9/2 . because two 9 ohm resistances are in parallel. so by using ohms LAW V=IR we get I = 9/4.5= 2 ampere. 2. for potential diff across 5 ohms it will be (current in the SECOND branch × 5 ) the current in both branches is identical since there are identical resistance in both branch . current in an branch= 1 ampere. so potential diff across 5 ohm resistance is= 1×5 = 5 volts. hope you like the solution.

Answer»

Answer:

1.As you can see the effective resistance is 9/2 . because two 9 ohm resistances are in parallel.

so by using ohms LAW V=IR

we get I = 9/4.5= 2 ampere.

2. for potential diff across 5 ohms it will be (current in the SECOND branch × 5 )

the current in both branches is identical since there are identical resistance in both branch . current in an branch= 1 ampere.

so potential diff across 5 ohm resistance is= 1×5 = 5 volts.

hope you like the solution.

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