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In 240 years ,a radioactive material remain 1/16th of its initial value find half life and decay constant of radioactive material |
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Answer»
ACTIVITY of radioactive substance at any time t is GIVEN by ⇒N=N
e −λt
given that N 0
N
= 16 1
at time t=40days ⇒ 16 1
=e −40λ
⇒e 40λ =16 ⇒λ= 40 ln16
we KNOW that t 2 1
= λ ln2
after putting the value of λ in above equation ⇒t 2 1
= ln16 ln2
×40=10 This is the right ANSWER for your question. |
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