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In a Arrhenius equation for a certain reaction, the values of `A and E_(a)` ( energy of activation)are `4xx10^(13)s^(-1)` and `98.6KJ mol^(-1)`, respectively. If the reaction of first order at, what temperature will its life periof be `10 min`. |
Answer» Accroding to Arrhenius equation, `k=Ae^(-E_(a)//RT)` or `log_(e)k=log_(e)A-(E_(a))/(RT)` or `2.303 log_(10)k=2.303 log _(10)A-(E_(a))/(RT)` For a first order reaction `t_(1//2)=(0693)/(k)` So, `k=(0.693)/(600) sec^(-1)(t_(1//2)=10min=600 sec)` `=1.1xx10^(-3)sec^(-1)` Hence, log `(1.1xx10^(-3))=log(4xx10^(13))-(98.6xx10^(3))/(2.303xx8.314xxT)` T=310.95K` |
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