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InterviewSolution
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In a certain hypothetical radioactive decay process, species A decays into spesies `B` and species `B` decays into` C` according to the reactions `{:(A rarr 2B +"particles +energy"),(B rarr 2C+"particles +energy"):}` The decay constant for species `B` is `lambda_(2)=100 s^(-1)`. Initially, `10^(4)` moles of species of `A` were present while there was no none of `B` and `C`. It was found that species `B` reaches its maximum number at a time `t_(0)=2 1n(10)s`. Calcualte the value of maximum number of moles of `B`. |
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Answer» Correct Answer - `2` `(dN_A)/(dt) = - lambda_(1) N_(A), (dN_(B))/(dt)=2 lambda_(1) N_(A)-lambda_(2)N_(B)` N_(B) =maximum rArr `(dN_(B))/(dt)=0` `rArr 2 lambda_(1) N_(A)=lambda_(2)N_(B_(max))` or `N_(B_(max))=(2 lambda_(1))/(lambda_(2)) N_(A)` or `N_(B_(max)) =(2 lambda_(1))/(lambda_(2)) M_(0)e^(- lambda_(2)t )=2`. |
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