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In a certain reaction, `10%` of the reactant decomposes in one hour, `20%` in two hours, `30%` in theee hours, and so on. The dimenison of the velocity constant (rate constant) areA. `hr^(-1)`B. `Mol L^(-1) hr^(-1)`C. `L mol^(-1) s^(-1)`D. `Mol s^(-1)` |
Answer» Correct Answer - B form the question, it is clear `t_(1//2) prop a`. Hence, zero order reaction. So, dimenison of `k = mol L^(-1) hr^(-1)`. For zero order: `t = (x)/(k) or k = (x)/(t)` If `t = t_(10%) = 10 min, x = 10`, Then, `k = (10)/(10) = 1 mol L^(-1) t^(-1)`. If `t = t_(20%) = 20 min, x = 20`, Then, `k = (20)/(20) = 1 mol L^(-1) t^(-1)`. ismilarly, for `30%` and so on. Thus, reaction is of zero order. |
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