1.

In a certain town, males and females form 50% of the population. It is known that 20% of the males and 5 % of the females are unemployed.A research student studying unemployment situations selects unemployed persons at random. What is the probability that the person selected is a) male and b)female?

Answer»

<P>Answer:

1/10 for (b)

(a) 2/5

Explanation:

The number of OUTCOMES is here is 50% so, n(s)=50

males are 20%so,n(a)=20

females are 5%so,n(b)=5

(A) P(a)= n(a)/n(s)= 20/50= 2/5

(B) P(a)= n(b)/n(s)= 5/50= 1/10

20/50= 2 is for ×10

5 is for ×10

5/50 = 1 is for ×5

10 is for ×5

I HOPE you are satisfied



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