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In a common base configuration (transistor circuit) `I_(E)=1mA, I_(C)=0.95mA`. The value of base current isA. 195 mAB. 0.05 mAC. 105 mAD. 0.95 mA |
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Answer» Correct Answer - B For a common base transistor, `I_(E)=I_(B)+I_(C )` `1mA=I_(B)=0.95mA` `I_(B)=0.05mA` |
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