1.

In a common base configuration (transistor circuit) `I_(E)=1mA, I_(C)=0.95mA`. The value of base current isA. 195 mAB. 0.05 mAC. 105 mAD. 0.95 mA

Answer» Correct Answer - B
For a common base transistor,
`I_(E)=I_(B)+I_(C )`
`1mA=I_(B)=0.95mA`
`I_(B)=0.05mA`


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