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In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. `5xx10^(-6)V`B. `12.50 xx 10^(-6)V`C. 1.25 VD. 125.0 V |
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Answer» Correct Answer - C `A_(v)=(Delta V_(0))/(DeltaV_(i))=beta(R_(0))/(R_(i)) and DeltaV_(0)=DeltaV_(i)xxbeta(R_(0))/(R_(i))` `therefore DeltaV_(0)= 10xx50 xx(500)/(2000)` `DeltaV_(0)=1250mV=1.25V` |
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