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In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. 1.25 VB. 12.5 VC. 125VD. 1250 V |
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Answer» Correct Answer - A `R_(0)=5000 Omega , R_(i)=2000, V_(i)=10 mV, beta=50, V_(0)=?` `A_(v)=(V_(0))/(V_(i))=beta*(R_(0))/(R_(i))` `V_(0)=betaV_(i)(R_(0))/(R_(i))` `=50xx10xx10^(-3)xx(5000)/(2000)` `=50xx10xx2.5xx10^(-3)` `=1250xx10^(-3)V` `=1.25 V` |
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