1.

In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. 1.25 VB. 12.5 VC. 125VD. 1250 V

Answer» Correct Answer - A
`R_(0)=5000 Omega , R_(i)=2000, V_(i)=10 mV, beta=50, V_(0)=?`
`A_(v)=(V_(0))/(V_(i))=beta*(R_(0))/(R_(i))`
`V_(0)=betaV_(i)(R_(0))/(R_(i))`
`=50xx10xx10^(-3)xx(5000)/(2000)`
`=50xx10xx2.5xx10^(-3)`
`=1250xx10^(-3)V`
`=1.25 V`


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