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In a ΔABC, right angled at A, if tan C = √3, find the value of sin B cos C + cos B sin C. |
Answer» In a ΔABC, right angled at A, tan C = √3 i.e ∠C = 60° and ∠B = 90 - 60 = 30° Sin C = Sin 60° = √3/2 Cos C = Cos 60° = 1/2 Sin B = Sin 30° = 1/2 Cos B = Cos 30° = √3/2 According to the question, sin B cos C + cos B sin C = (1/2) (1/2) + (√3/2) (√3/2) = 1/4 + 3/4 = 1 |
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