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In a `DeltaABC`, if 2AC=3CB, then 2OA+3OB is equal toA. 5OCB. `-OC`C. `OC`D. none of these |
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Answer» Correct Answer - A `2OA+3OB=2(OC+CA)+3(OC+CB)` `=5OC+2CA+3CB=5OC(because2CA=-3CB)`. |
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