1.

In a `DeltaABC`, if 2AC=3CB, then 2OA+3OB is equal toA. 5OCB. `-OC`C. `OC`D. none of these

Answer» Correct Answer - A
`2OA+3OB=2(OC+CA)+3(OC+CB)`
`=5OC+2CA+3CB=5OC(because2CA=-3CB)`.


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