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In a first order reaction `A rarr` product, 80% of the given sample of compound decomposes in 40 min. What is the half life period of the reaction ? |
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Answer» Given, 80% of sample decomposes Time = 40 min. `t_(1//2)` (half life = ? ) Consider, initial concentration of sample is 100. `:.[A]_(o)=100` `:.[A]_(t)=100-80` `=20 ` Final concentration `:.k=(2.303)/(t)log_(10).([A]_(o))/([A]_(t))` `=(2.303)/(40)log_(10).(100)/(20)` `=(2.303)/(40) log_(10)5` `=(2.303)/(40)xx0.6989` `k=0.04024` `:.` Half life `t_(1//2)=(0.693)/(k)` `=(0.693)/(0.04024)=17.22` Half-life is `17.22` min. |
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