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In a first order reaction, The concentration of reactant is reduced to 1/8th of the initial concentration in 75 minutea at 298 K. What is the half period of the reaction in minutes?A. 50 minB. 15 minC. 30 minD. 25 min |
Answer» Correct Answer - D Let a = 1, a - x = 1/8 th, t == 75 min `k = (2.303)/(t) "log" (a)/(a - x) = (2.303)/(75) "log" (1)/(1//8) = (2.303 xx 0.903)/(75) "min"^(-1)` for first order reaction, `t_(1//2) = (0.693)/(k) = (0.693 xx 75)/(2.303 xx 0.903) = 25` min |
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