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In a first order reaction, the concentration of the reactants is reduced to `25%` in one hour. The half-life period of the reactions isA. 2 hrsB. 2hrsC. `1//2` hrsD. `1//4` hrs |
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Answer» Correct Answer - C `k=(2.030)/(t)log.((a)/(a-x))` `k=(2.303)/(1) log. ((100)/(5))=2xx0.693` `t_(1//2)=(0.693)/(k)=(0.693)/(2xx0.693)=(1)/(2)hr` |
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