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In a first order reaction , the concentration of the reactant is reduced to 1/8 of the initial concentration in 75 minutes at 298 K . What is the half-life period of the reaction in minutesA. 50B. 15C. 45D. 25 |
Answer» Correct Answer - d Let a = 1 , a-x = 1/8 , t = 75 min For first order reaction `k = (2.303)/(t)` log `(a)/(a-x)` `k = (2.303)/(75)` log `(1)/(1//8) = (2.303 xx 0.903)/(75) "min"^(-1)` For first order reaction `t_(1//2) = (0.693)/(k) = (0.693 xx 75)/(2.303 xx 0.903) = 25` min . |
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