In a Geiger-Marsden experiment, what is the distance of closest approa

1.	In a Geiger-Marsden experiment, what is the distance of closest approach to the nucleus of a 7.7 MeValpha-particle before it comes momentarily to rest and reverses its direction?WHAT IS Z VALUE..SPAMMERS BE AWAY...IF FOUND WILL BE BANNED..❌
Answer» Answer: Closest distance of approach of alpha particle towards GOLD nuclei is $r = 1.48 \times 10^{-14} m$ Explanation: In this EXPERIMENT alpha particles are PROJECTED towards the nuclei of gold so here INITIAL kinetic energy of alpha particle is converted into electrostatic POTENTIAL energy of alpha particle + gold nuclei So we will have $\frac{k(e)(ze)}{r} = KE$ $\frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r} = 7.7 \times 1.6 \times 10^{-13}$ $\frac{1.82 \times 10^{-26}}{r} = 1.23 \times 10^{-12}$ $r = 1.48 \times 10^{-14} m$ #Learn Topic : Electrostatic potential energy brainly.in/question/12798714