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In a given process on an ideal gas, `dW=0` and `dQ` is negative, then for the gas:A. The temperature will decreaseB. The volume will increaseC. The pressure will remain constantD. The temperature will increase |
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Answer» Correct Answer - A `q=dU+(-dW)` if `dW=0, q=-ve , dU` will be `-ve` or `T` will decrease. |
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