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In a half wave rectifier, a p-n junction diode with internal resistance 20 ohm is used. If the load resistance of 2 ohm is used in the circuit, then find the efficiency of this half wave rectifier. |
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Answer» Internal resistance `( r_(f)) = 20 Omega ` `R_(L) = 2k Omega = 2000 Omega ` `eta = ( 0.406R_(L))/(r_(f) + R_(L)) = ( 0.406 xx 2000)/( 20+ 2000) xx 100 = ( 812 xx 100)/( 2020)` `eta = 40.2 %` |
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