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In a half wave rectifier output is taken across a `90 ohm` load resistor. If the resistance of diode in forward biased condition is `10 ohm`, the efficiency of rectification of `ac` power into `dc` power is.A. 0.406B. 0.812C. 0.7308D. 0.3654 |
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Answer» Correct Answer - D `eta=0.406xx(6)/(R_(l)+r_(f))=(0.406xx90)/(90+10)` `=36.54%` |
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