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In a house, 3 bulbs of 100 watt each are lighted for 5 hours daily, 2 fans of 50 watt each are used for 10 hours daily and an electric heater of 1kWh is used for half an hour daily. Calculate the total energy consumed in a month of 31 days and its cost at the rate of ₹ 3.60/kWh |
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Answer» Total Energy consumed is 108.5 Kwh and COST is Rs 390.6 Explanation: We Have :- 3 bulbs of 100 watt each lighted for 5 hours daily 2 fans of 50 watt each used for 10 hours daily Electric HEATER of 1.00 kW used for an hour daily Rate of 3.60 per Kwh To FIND :- Total Energy consumed in a month of 31 days and Cost Formula Used :- Energy consumed = Power × time Solution :- Energy consumed by Bulbs :- Power = 3 * 100 watt = 300 watt = 0.3 Kw Time = 5 hours in one day = 5 * 31 in a month = 155 hours Energy = 0.3 * 155 = 46.5 Kwh Energy consumed by Fans :- Power = 2 * 50 = 100 watt = 0.1 Kw Time = 10 hours in one day = 10 * 31 in a month = 310 hours Energy = 0.1 * 310 = 31 Kwh Energy consumed by Heater :- Power = 1 Kw Time = 1 hours in one day = 1 * 31 in a month = 31 hours Energy = 1 * 31 = 31 Kwh Total Energy consumed = 46.5 + 31 + 31 = 108.5 Kwh Cost :- 1 Kwh = Rs 3.60 108.5 Kwh = Rs 3.60 * 108.5 = Rs 390.6 Total Energy consumed is 108.5 Kwh and Cost is Rs 390.6 |
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