in a hydro electric power , 1000×10power3kg water falls through a hei

1.	in a hydro electric power , 1000×10power3kg water falls through a height of 51m in one second. calculate (1) work done by the following water and (2) power generated under ideal conditions
Answer» Answer: Given: MASS of WATER = 1000 × 10³ kg Height through which it falls = 51 metres Time TAKEN = 1 second To find: Work done by water Power generated under ideal conditions Concept: For calculation of work done , we can EASILY understand that the whole Potential energy of the water at that height will be converted to work done while falling. This is because gravitational FORCE is an conservative force. And finally power can be calculated as the rate of work done . Calculation: $\boxed{potential \: energy = m \times g \times h}$ $= > PE = {10}^{6} \times 10 \times 51$ $= > PE = 51 \times {10}^{7} joules$ This whole PE will be converted to work done by water. $\boxed{ \red{ \therefore \: work = 51 \times {10}^{7} \: joules }}$ Now , Calculation of power : $power = \dfrac{work}{time}$ $= > power = \dfrac{51 \times {10}^{7} }{1}$ $= > power = 51 \times {10}^{7} watts$ $\boxed{ \red { power = 510000 \: kilowatts}}$

in a hydro electric power , 1000×10power3kg water falls through a height of 51m in one second. calculate (1) work done by the following water and (2) power generated under ideal conditions

Answer»

Answer:

Given:

MASS of WATER = 1000 × 10³ kg

Height through which it falls = 51 metres

Time TAKEN = 1 second

To find:

Work done by water
Power generated under ideal conditions

Concept:

For calculation of work done , we can EASILY understand that the whole Potential energy of the water at that height will be converted to work done while falling.

This is because gravitational FORCE is an conservative force.

And finally power can be calculated as the rate of work done .