In a hypothetical atom, mass of electron is doubled, value of atomic number is `Z = 4`. Find wavelength of photon when this electron jumps from 3rd excited state to 2nd orbit.

In a hypothetical atom, mass of electron is doubled, value of atomic n

1.	In a hypothetical atom, mass of electron is doubled, value of atomic number is `Z = 4`. Find wavelength of photon when this electron jumps from 3rd excited state to 2nd orbit.
Answer» Correct Answer - A `E prop (Z^2)/(n^2)`prop m` Mass is doubled, `Z = 4` and 3rd excited state means `n =4`, second orbit means `n = 2` for these` values, we have. `E_4 =- 13.6xx2((4)/(4))^2 =- 27.2eV` and `E_2 =-13.6xx2((4)/(2))^2 =- 108.8eV` `lmabda(inÅ)= (12375)/(DeltaE(in eV)) = (12375)/(E_4 - E_2)` `=(12375)/(-27.2+108.8)` `:. lambda = 151.65Å`

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In a hypothetical atom, mass of electron is doubled, value of atomic number is `Z = 4`. Find wavelength of photon when this electron jumps from 3rd excited state to 2nd orbit.

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