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In a process, `701 J` of heat is absorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?A. `-464J`B. `+464J`C. `+307J`D. `-307J` |
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Answer» Correct Answer - C We know, internal energy change, `DeltaE=q+W` `=+701J+(-394J)=+307J`. Hence, internal energy of the system increases by 307 J. |
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