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In a reaction, `2A to` Products, the concentration of A decreases from 0.5 mol `L^(-1)` to 0.4 mol `L^(-1)` in 10 minutes. Calculate the rate during this interval. |
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Answer» For the reaction, `2A to `products. Avergage rate = `-1/2(Delta[A])/(dt) = -1/2((0.4-0.5) mol^(-1))/(10 min)` `=((0.1)molL^(-1))/(20 min) = 0.005 mol L^(-1)min^(-1)` |
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