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In a reaction the initial concentration of the reactants increase four fold and the rate becomes eight times its initial value . The order of the reaction isA. `2.0`B. `3.5`C. `2.5`D. `1.5` |
Answer» Correct Answer - d Rate = `KC^(n)` Or r = `KC^(n) " "… (i)` `8r = K(4C)^(n) " " … (ii)` Dividing Eq. (ii) by (i) , we get `2^(3) = 2^(2n)` or 2 n =3 n = 1.5. |
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