1.

In a reaction the initial concentration of the reactants increase four fold and the rate becomes eight times its initial value . The order of the reaction isA. `2.0`B. `3.5`C. `2.5`D. `1.5`

Answer» Correct Answer - d
Rate = `KC^(n)`
Or r = `KC^(n) " "… (i)`
`8r = K(4C)^(n) " " … (ii)`
Dividing Eq. (ii) by (i) , we get
`2^(3) = 2^(2n)`
or 2 n =3
n = 1.5.


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