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    				| 1. | In a regualr hexagon ABCDEF, `A vecB = vec a, B vec C = vecb and C vec D = vec c. " Then " A vec E = `A. `veca + vec b + vec c`B. `2 veca + vec b + vec c `C. `vec a + vec c `D. `vec a + 2 vec b + 2 vec c ` | 
| Answer» Correct Answer - C We have, `A vec B = vec a , B vec C = vec b and C vec D = vec c ` `therefore A vec C = vec a + vec b ` In ` Delta ACD`, we have `A vec C + C vec D = A vec D ` `rArr vec a + vec b + vec c = A vec D ` In ` Delta AED`, we have `A vec D + D vec E = A vec E ` `rArr vec a + vec b + vec c - vec a = A vec E " " [ because D vec E = B vec A = - vec a ]` ` rArr A vec E = vec b + vec c ` | |