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In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?A. `1.05 cm`B. `115.5 cm`C. `92.5 cm`D. `113.5 cm`

Answer» Correct Answer - A
For end correction `x`, `(l_2+x)/(l_1+x)=(3lamda//4)/(lamda//4)=3`
`x=(l_2-3l_1)/(2)=(70.2-3xx22.7)/(2)=1.05cm`


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