InterviewSolution
Saved Bookmarks
| 1. |
In a resonance tube experiment, two successive resonances are heard at 15 cm 48 cm. End correction will beA. 1.5cmB. 3cmC. 2.5cmD. 1cm |
|
Answer» Correct Answer - A `rho=(l_2-3l_1)/(2) = (48-3xx15)/)(2)` `rho = (48-45)/(2) = 3/2 = 1/5cm` |
|