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In a reverse biased diode, when the applied voltage changes by `1V`, the current is found to change by `0.5muA`. The reversebiase resistance of the diode isA. `2xx10^(5)Omega`B. `2xx10^(6)Omega`C. `200Omega`D. `2Omega` |
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Answer» Correct Answer - B `(DeltaV)/(DeltaI)=(1)/(0.5xx10^(-6))=2xx10^(6)Omega` |
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