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In a reversible process, `Delta S_(sys) + Delta S_(surr)` isA. `gt 0`B. `lt 0`C. `ge 0`D. `= 0` |
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Answer» Correct Answer - D "Reversible" under strict thermodynamics sense is a special way of carrying out a porcess such that the system is at times in perfect equilibrium with its surroundings. Thus, accoridng to the second law of thermodynamics, `Delta S_(uni) = Delta S_(sys) + Delta S_(surr) = 0` |
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