In a right angle ∆ABC, AB=12, BC=5 and Angle ABC=90°. Find AC.(a) 169(b) 13(c) 17(d) 14This question was posed to me in an online interview.I need to ask this question from Pythagorean Triplet in division Squares and Square Roots of Mathematics – Class 8

In a right angle ∆ABC, AB=12, BC=5 and Angle ABC=90°. Find AC.(a) 1

1.	In a right angle ∆ABC, AB=12, BC=5 and Angle ABC=90°. Find AC.(a) 169(b) 13(c) 17(d) 14This question was posed to me in an online interview.I need to ask this question from Pythagorean Triplet in division Squares and Square Roots of Mathematics – Class 8
Answer» The correct option is (B) 13 For explanation: This triangle is a right angled triangle so we can use PYTHAGORAS THEOREM. THEREFORE, we get ∴ AC^2 = AB^2 + BC^2 ∴ AC^2 = 12^2 + 5^2 ∴ AC^2 = 144 + 25 ∴ AC^2 = 169 ∴ AC = 13.

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In a right angle ∆ABC, AB=12, BC=5 and Angle ABC=90°. Find AC.(a) 169(b) 13(c) 17(d) 14This question was posed to me in an online interview.I need to ask this question from Pythagorean Triplet in division Squares and Square Roots of Mathematics – Class 8

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