In a right angle triangle length of base is 4cm and perpendicular comp

1.	In a right angle triangle length of base is 4cm and perpendicular component is 3cm find sin theta,cos theta,tan theta
Answer» Explanation: sin THETA = opposite /HYPOTENUSE cos theta =adjecant /hypotenuse (hypotenuse)^2= (base)^2+(perpendicular component)^2 (4)^2+(3)^2=16+9=25 hence hypotenuse =5cm hence sin theta =4/5 cos theta=3/5 than theta= sin theta/cos theta =4/3

In a right angle triangle length of base is 4cm and perpendicular component is 3cm find sin theta,cos theta,tan theta

Answer»

Explanation:

sin THETA = opposite /HYPOTENUSE

cos theta =adjecant /hypotenuse

(hypotenuse)^2= (base)^2+(perpendicular component)^2

(4)^2+(3)^2=16+9=25

hence hypotenuse =5cm

hence sin theta =4/5

cos theta=3/5

than theta= sin theta/cos theta =4/3

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In a right angle triangle length of base is 4cm and perpendicular component is 3cm find sin theta,cos theta,tan theta

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