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InterviewSolution
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In a second order reaction, when the concentration of both the reactants are equal, the reaction is completed `20%` in 500 s. How long would it take for the reaction to go to `60%` completion?A. 3000sB. 5000sC. 1000 sD. 2000s |
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Answer» Correct Answer - A a) For the second order reaction, `k=1/(t xx a). (X/(a-x))` According to available data, in the first case t=500s , a=100 a-x `=80%` of 100 = 80 `k=(1 xx 20)/(500s xx 100 xx 80)= 5 xx 10^(-6)s^(-1)` In the second case, a=100 `(a-x) = 40%` of 100 = 40 `t=(1 xx 60)/((5 xx 10^(-6)s^(-1)) xx (100 xx 40))=3000s`. |
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