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In a simultaneous throw of pair of dice .find the probability of getting the total more than 7. |
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Answer» Here n(S)=(6*6)=36 let E=event of getting a total more than 7 ={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5 ),(6,6)} P(E)=n(E)/n(S)=15/36=5/12. |
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