In a survey of 60 people, it was found that 25 people read newspaper H

1.	In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and T, 8 read both T and I, 3 read all three newspapers. Find: the numbers of people who read at least one of the newspapers
Answer» Total number of People n(P) = 60. n(H) =25. n(T) = 26. n(I) = 26. n (H ∩ I) = 9 n (H ∩ T) = 11 n (T ∩ I) = 8 n (H ∩T ∩ I) = 3 The people who read at least one newspaper would be n(H or I or T) = n(H∪I∪T) We know, n(H∪I∪T) = n(H)+n(I)+n(T) – n (H ∩ I)– n (H ∩ T)– n (T ∩ I)+ n (H ∩T ∩ I) n(H∪I∪T) = 25+26+26–9–11–8+3 n(H∪I∪T) = 52. There are 52 people who read at least one newspaper.

In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, 11 read both H and T, 8 read both T and I, 3 read all three newspapers. Find: the numbers of people who read at least one of the newspapers

Answer»

Total number of People n(P) = 60.

n(H) =25.

n(T) = 26.

n(I) = 26.

n (H ∩ I) = 9

n (H ∩ T) = 11

n (T ∩ I) = 8

n (H ∩T ∩ I) = 3

The people who read at least one newspaper would be n(H or I or T) = n(H∪I∪T)

We know,

n(H∪I∪T) = n(H)+n(I)+n(T) – n (H ∩ I)– n (H ∩ T)– n (T ∩ I)+ n (H ∩T ∩ I)

n(H∪I∪T) = 25+26+26–9–11–8+3

n(H∪I∪T) = 52.

There are 52 people who read at least one newspaper.