In a survey of 600 students ina school, 150 students were found to be – InterviewSolution

InterviewSolution

1.	In a survey of 600 students ina school, 150 students were found to be taking tea and 225 taking coffee, 100were taking both tea and coffee. Find how many students were taking neithertea nor coffee?
Answer» Let universal set U is the set of all students of the survey and T is the set of student taking tea and C is the set of students taking coffee then `n(U)=600,n(T)=150,n(C)=225` and `n(T capC)=100` `:. n(T cup C)-n(T)+n(C)-n(T cap C)` `150 + 225 - 100` `= 275` Number of students who take neither tea nor coffee `= n(U)-n(T cup C)` `= 600-275 = 325` Therefore, 325 students take neither tea nor coffee.

Discussion

No Comment Found

Related InterviewSolutions

If A and B are two sets such that n (A ∪ B) = 50, n (A) = 28 and n (B) = 32, find n (A ∩ B).
The solution of `8x = 6 (mod 14)` isA. [8],[6]B. [8],[14]C. [6],[13]D. [8],[14],[16]
Find congruent solutions of `155-=7` (mod 4).
Find all congruent solutions of `8x -= 6` (mod 14).
Solve for X, if IX S 1. Two finite sets have m and n elements. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. Find the value of m and n. respectively. can be the (f A and B be two sets containing 3 and 6 elements What
Two finite sets have m and n elements. The total number of subsets of first set is 56 more than the total number of subsets of the second set. Find the value of m and n.
Two finite sets have m and n elements respectively. The total number of subsets of first set is 56 more than the total number of subsets of the second set. The values of m and n respectively are. (A) 7, 6 (B) 5, 1 (C) 6, 3 (D) 8, 7
Two finite sets have m and n elements. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. The value of m and n isA. 7, 6B. 6, 3C. 5, 1D. 8, 7
If U = {2, 3, 5, 7, 9} is the universal set and A = {3, 7}, B = {2, 5, 7, 9}, then prove that:(i) (A ∪ B)’ = A’ ∩ B’(ii) (A ∩ B)’ = A’ ∪ B’
Let A and B be sets. If A ∩ X = B ∩ X = Φ and A ∪ X = B ∪ X for some set X,show that A = B.(Hints A = A ∩ (A ∪ X), B = B ∩ (B ∪ X) and use distributive law)