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In a transistor connected in a common emitter mode `R_C = 4kOmega, R_1 = 1kOmega, I_C = 1mA` and `I_B = 20 muA`. Find the voltage gain.A. 100B. 200C. 300D. 400 |
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Answer» Correct Answer - B Voltage gain, `A_V=(betaR_C)/R_I=I_C/I_BxxR_C/R_I` `=(1xx10^(-3)xx4xx10^3)/(20xx10^(-6)xx1xx10^3)=200` |
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