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In a transistor, `I_(c)` = 20 mA, `I_(b)` =1 mA. What will be the value of `alpha` ?A. 20/21B. `1//20`C. 21/20D. 20 |
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Answer» Correct Answer - A `alpha=(I_(c))/(I_(e))=(I_(c))/(I_(e)+I_(b))=(20)/(20+1)=(20)/(21)` |
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