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In a triode, `gm=2xx10^(-3)ohm^(-1) , mu=42`, resistance load, R = 50 kilo ohm. The voltage amplification obtained from this triode will beA. 30.42B. 29.57C. 28.18D. 27.15 |
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Answer» Correct Answer - B As, `A_(v)=(muR)/(r_(p)+R)=(muR)/((mu//g_(m))+R)` `=(42xx(50xx10^(3)))/(42//(2xx10^(-3))+50xx10^(3))=29.57` |
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