1.

In ∆ABC and ∆PQR, in a one to one correspondence \(\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ},\) then(A) ∆PQR – ∆ABC (B) ∆PQR – ∆CAB (C) ∆CBA – ∆PQR (D) ∆BCA – ∆PQR

Answer»

Correct answer is

(B) ∆PQR – ∆CAB



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