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In ∆ABC and ∆PQR, in a one to one correspondence \(\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ},\) then(A) ∆PQR – ∆ABC (B) ∆PQR – ∆CAB (C) ∆CBA – ∆PQR (D) ∆BCA – ∆PQR |
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Answer» Correct answer is (B) ∆PQR – ∆CAB |
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