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InterviewSolution
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In an agriculture experiment, a solution containing 1 mole of a radioactive meterial `(t_(1//2)=14.3 days)`was injected into the roots of a plants.the plant was allowed 70 hours to settle down and then activity eas measured in its fruit. If the activity measured was `1 mu Ci` what per cent of activity is transmitted from the root to the fruit in steady state? |
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Answer» Correct Answer - A::B `R_0=lambdaN=(0.693)/(14.3xx3600xx24)xx6.02xx10^23` per sec `=3.37xx10^17` per sec After 70 hours activity, `R=R_0e^(-lambdat)=(3.37xx10^17)e^(-(0.693//14.3xx24)(70))` `=2.92xx10^17` per sec In fruits activity was observed `1muCi` or `3.7xx10^4` per sec. Therefore, percentage of activity transmitted from root to the fruit. `=(3.7xx10^4)/(2.92xx10^17)xx100` `1.26xx10^-11%` |
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