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In an exothermic reaction `X rarr Y`, the activation energy is `100 kJ mol^(-1)` of `X`. The enthalphy of the reaction is `-140 kJ mol^(-1)`. The activation energy of the reverse reaction `Y rarr X` is A. `40 kJ mol^(-1)`B. `340 kJ mol^(-1)`C. `240 kJ mol^(-1)`D. `100 kJ mol^(-1)` |
Answer» Correct Answer - C For `X rarr Y:(E_(a))_(f) = 100 kJ mol^(-1)` `Delta H = -140 kJ mol^(-1) =| 140 kJ mol^(-1)|` Form the figure above `(E_(a))_(b) = (E_(a))_(f) + Delta H` `= 100 + 140 + 240 = kJmol^(-1)` |
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