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In an ore containing uranium, the ratio of ^238U` to `206Pb` nuclei is 3. Calculate the age of the ore, assuming that all the lead present in the ore is the final stable product of `^238U`. Take the half-life of `^238U` to be `4.5xx10^9` years. |
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Answer» Correct Answer - A `(U^238)/(Pb^206)=3/1` `N_0=3+1=4` `N=3` `N=N_0e^(-lambdat)` …(i) `lambda=(1n2)/(t_(1//2)` …(ii) From Eqs. (i) and (ii), we get `t=1.88xx10^9 yr` |
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