Related InterviewSolutions

• In equation ℴ = \(\frac{2}{T}(\frac{r^2-1}{1+r^2+2rcosω})\), if r > 1 then ℴ > 0 and then mapping from s-plane to z-plane occurs in which of the following order?(a) LHP in s-plane maps into the inside of the unit circle in the z-plane(b) RHP in s-plane maps into the outside of the unit circle in the z-plane(c) All of the mentioned(d) None of the mentionedThis question was addressed to me in class test.My question is based upon IIR Filter Design by the Bilinear Transformation in division Discrete Time Systems Implementation of Digital Signal Processing
• In Nth order differential equation, the characteristics of bilinear transformation, let z=re^jw,s=o+jΩ Then for s = \(\frac{2}{T}(\frac{1-z^{-1}}{1+z^{-1}})\), the values of Ω, ℴ are(a) ℴ = \(\frac{2}{T}(\frac{r^2-1}{1+r^2+2rcosω})\), Ω = \(\frac{2}{T}(\frac{2rsinω}{1+r^2+2rcosω})\)(b) Ω = \(\frac{2}{T}(\frac{r^2-1}{1+r^2+2rcosω})\), ℴ = \(\frac{2}{T}(\frac{2rsinω}{1+r^2+2rcosω})\)(c) Ω=0, ℴ=0(d) NoneI had been asked this question during an internship interview.This interesting question is from IIR Filter Design by the Bilinear Transformation topic in portion Discrete Time Systems Implementation of Digital Signal Processing
• In equation ℴ = \(\frac{2}{T}(\frac{r^2-1}{1+r^2+2rcosω})\) if r < 1 then ℴ < 0 and then mapping from s-plane to z-plane occurs in which of the following order?(a) LHP in s-plane maps into the inside of the unit circle in the z-plane(b) RHP in s-plane maps into the outside of the unit circle in the z-plane(c) All of the mentioned(d) None of the mentionedThis question was posed to me during an interview for a job.My question comes from IIR Filter Design by the Bilinear Transformation in division Discrete Time Systems Implementation of Digital Signal Processing
• In the Bilinear Transformation mapping, which of the following are correct?(a) All points in the LHP of s are mapped inside the unit circle in the z-plane(b) All points in the RHP of s are mapped outside the unit circle in the z-plane(c) All points in the LHP & RHP of s are mapped inside & outside the unit circle in the z-plane(d) None of the mentionedI got this question in quiz.The above asked question is from IIR Filter Design by the Bilinear Transformation topic in portion Discrete Time Systems Implementation of Digital Signal Processing
• What is the system function of the equivalent digital filter? H(z) = Y(z)/X(z) = ?(a) \(\frac{(\frac{bT}{2})(1+z^{-1})}{1+\frac{aT}{2}-(1-\frac{aT}{2}) z^{-1}}\)(b) \(\frac{(\frac{bT}{2})(1-z^{-1})}{1+\frac{aT}{2}-(1+\frac{aT}{2}) z^{-1}}\)(c) \(\frac{b}{\frac{2}{T}(\frac{1-z^{-1}}{1+z^{-1}}+a)}\)(d) \(\frac{(\frac{bT}{2})(1-z^{-1})}{1+\frac{aT}{2}-(1+\frac{aT}{2}) z^{-1}}\) & \(\frac{b}{\frac{2}{T}(\frac{1-z^{-1}}{1+z^{-1}}+a)}\)This question was addressed to me in an interview for job.I want to ask this question from IIR Filter Design by the Bilinear Transformation in chapter Discrete Time Systems Implementation of Digital Signal Processing
• We use y{‘}(nT)=-ay(nT)+bx(nT) to substitute for the derivative in y(nT) = \(\frac{T}{2} [y^{‘} (nT)+y^{‘} (nT-T)]+y(nT-T)\) and thus obtain a difference equation for the equivalent discrete-time system. With y(n) = y(nT) and x(n) = x(nT), we obtain the result as of the following?(a) \((1+\frac{aT}{2})Y(z)-(1-\frac{aT}{2})y(n-1)=\frac{bT}{2} [x(n)+x(n-1)]\)(b) \((1+\frac{aT}{n})Y(z)-(1-\frac{aT}{n})y(n-1)=\frac{bT}{n} [x(n)+x(n-1)]\)(c) \((1+\frac{aT}{2})Y(z)+(1-\frac{aT}{2})y(n-1)=\frac{bT}{2} (x(n)-x(n-1))\)(d) \((1+\frac{aT}{2})Y(z)+(1-\frac{aT}{2})y(n-1)=\frac{bT}{2} (x(n)+x(n+1))\)This question was addressed to me by my school principal while I was bunking the class.Question is from IIR Filter Design by the Bilinear Transformation in chapter Discrete Time Systems Implementation of Digital Signal Processing
• The approximation of the integral in y(t) = \(\int_{t_0}^t y'(τ)dt+y(t_0)\) by the Trapezoidal formula at t = nT and t0=nT-T yields equation?(a) y(nT) = \(\frac{T}{2} [y^{‘} (nT)+y^{‘} (T-nT)]+y(nT-T)\)(b) y(nT) = \(\frac{T}{2} [y^{‘} (nT)+y^{‘} (nT-T)]+y(nT-T)\)(c) y(nT) = \(\frac{T}{2} [y^{‘} (nT)+y^{‘} (T-nT)]+y(T-nT)\)(d) y(nT) = \(\frac{T}{2} [y^{‘} (nT)+y^{‘} (nT-T)]+y(T-nT)\)I had been asked this question in an interview.This interesting question is from IIR Filter Design by the Bilinear Transformation topic in chapter Discrete Time Systems Implementation of Digital Signal Processing
• Is IIR Filter design by Bilinear Transformation is the advanced technique when compared to other design techniques?(a) True(b) FalseThis question was addressed to me in an internship interview.I want to ask this question from IIR Filter Design by the Bilinear Transformation topic in chapter Discrete Time Systems Implementation of Digital Signal Processing
• By combining \(\Delta=\frac{R}{2^{b+1}}\) with \(P_n=\sigma_e^2=\Delta^2/12\) and substituting the result into SQNR = 10 \(log_{10}⁡ \frac{P_x}{P_n}\), what is the final expression for SQNR = ?(a) 6.02b + 16.81 + \(20log_{10}\frac{R}{σ_x}\)(b) 6.02b + 16.81 – \(20log_{10}⁡ \frac{R}{σ_x}\)(c) 6.02b – 16.81 – \(20log_{10}⁡ \frac{R}{σ_x}\)(d) 6.02b – 16.81 – \(20log_{10}⁡ \frac{R}{σ_x}\)I got this question in a job interview.I need to ask this question from Analysis of Quantization Errors topic in section Discrete Time Systems Implementation of Digital Signal Processing
• In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_x}\), for R = 6σx the equation becomes?(a) SQNR = 6.02b-1.25 dB(b) SQNR = 6.87b-1.55 dB(c) SQNR = 6.02b+1.25 dB(d) SQNR = 6.87b+1.25 dBI got this question in examination.This interesting question is from Analysis of Quantization Errors in portion Discrete Time Systems Implementation of Digital Signal Processing